Name: Buy 2SA1015 A1015 PNP Transistor in Egypt @ 2.00 EGP
Brand: BJT Transistors
SKU: T_2SA1015
Price: 2.00 EGP
Availability: InStock

2SA1015 A1015 PNP Transistor

2.00 EGP

SKU: T_2SA1015 Categories: BJT Transistors

Pin Configuration

Pin No.	Pin Name	Description
1.	E	Emitter
2.	C	Collector
3.	B	Base

Features and Technical Specifications

Type: p-n-p
Power Dissipation: 0.4watts
High voltage and High current: Vceo = 50v and Ic = 150mA
Low Noise: 1dB
Case Material: molded plastic
Collector power dissipation: 400mW
DC current gain: 400
Collector Emitter and Collector Base breakdown voltage: 50Vdc
Base Emitter Saturation Voltage: 1.1Vdc
Collector Emitter Saturation Voltage: 0.3Vdc
Base Emitter voltage: 1.45Vdc
Complementary to 2SC1815
Operating Temperature and Storage Temperature: -55℃ to +150℃

Note: Complete technical details can be found in the A1015 Datasheet linked at the bottom of this page.

A1015 Equivalent Transistors

NTE290A, 2SA495, 2SA561, 2SA564A, 2SA573, 2SA675, 2SA705, 2SA850, 2SA999, KTA1015, BC212, BC257, BC307, BC557, 2N3494, 2SA781, KT3108A

Where to Use A1015 PNP Transistors?

The main use of 2SA1015 is for audio frequency amplifier applications. It can also be used for the switching purpose just like other PNP transistors. When use as an Audio frequency general purpose amplifier, can be operated in the active region. This transistor is further divided into four groups according to the DC current gain, O, Y, G, and L and has 140, 240, 400 and 700 hfe DC current gain respectively.

Group	DC current gain (hfe)
O	140
Y	240
G	400
L	700

Amplification factor usually determined in term of power, for calculating the current gain we use the formula:

Gain (hfe) = IC / IB

Where, IC is the collector current and IB is the base current of the circuit.

How to Use A1015 Transistor?

In the below circuit of LED flasher using 2SA1015, capacitor C1 and R1 used as frequency generator to Q1 transistor which is used as switch for Q2. And, Q2 is used for increasing the current. From capacitor C1 through R2 and LED, Q1 will work until the voltage drop increases across C1. As a result, Q2 starts conducting, and a current flows through LED and it turns ON.

While C1 discharged through R1 to a period of time, when C1 discharge out there would be no pressure to bias the base terminal of the Q1. Hence, the Q1 stop working which also stop Q2 to work. Therefore, LED turn OFF and C1 will start again and this cycle continues. And, the turning ON and OFF of LED seems as a flasher.